News from Mathnasium of Pflugerville
e (Euler's Number)
Aug 14, 2017
The number e is a famous irrational number, and is one of the most important numbers in mathematics.
The first few digits are:
2.7182818284590452353602874713527 (and more ...)
e is the base of the Natural Logarithms (invented by John Napier).
e is found in many interesting areas, so it is worth learning about.
There are many ways of calculating the value of e, but none of them ever give an exact answer, because e is irrational (not the ratio of two integers).
But it is known to over 1 trillion digits of accuracy!
For example, the value of (1 + 1/n)n approaches e as n gets bigger and bigger:
|n||(1 + 1/n)n|
The value of e is also equal to 1/0! + 1/1! + 1/2! + 1/3! + 1/4! + 1/5! + 1/6! + 1/7! + ... (etc)
(Note: "!" means factorial)
The first few terms add up to: 1 + 1 + 1/2 + 1/6 + 1/24 + 1/120 = 2.718055556
And you can try that yourself at Sigma Calculator.
To remember the value of e (to 10 places) just remember this saying (count the letters!):
Or you can remember the curious pattern that after the "2.7" the number "1828" appears TWICE:
2.7 1828 1828
And following THAT are the angles 45°, 90°, 45° in a Right-Angled Isosceles (two equal angles) Triangle:
2.7 1828 1828 45 90 45
(An instant way to seem really smart!)
An Interesting Property
Just for fun, try "Cut Up Then Multiply"
Let us say that we cut a number into equal parts and then multiply those parts together.
Now, ... how could we get the answer to be as big as possible, what size should each piece be?
Yes, the answer is bigger! But is there a best size?
The answer: make the parts "e" (or as close to e as possible) in size.
The winner is the number closest to "e", in this case 2.5.
Try it with another number yourself, say 100, ... what do you get?
Advanced: Use of e in Compound Interest
Often the number e appears in unexpected places.
For example, e is used in Continuous Compounding (for loans and investments):
Formula for Continuous Compounding
Why does that happen?
Well, the formula for Periodic Compounding is:
But what happens when the number of periods heads to infinity?
The answer lies in the similarity between:
|(1+r/n)n||and||(1 + 1/n)n|
|Compounding Formula||e (as n approaches infinity)|
By substituting x = n/r :
- r/n becomes 1/x and
- n becomes xr
Which is just like the formula for e (as n approaches infinity), with an extra r as an exponent.
So, as x goes to infinity, then (1+(1/x))xr goes to er
And that is why e makes an appearance in interest calculations!
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