ï‚·
There are 5 keys. One of them opens the first lock. If we are extremely
unlucky (the worst case scenario), we will have to try all 5 keys
to open the
first lock.
ï‚·
Once we figure out
the key
for the first lock,
there are 4 keys left.
In the
worst case scenario, we will have to try all 4 keys to open the second lock.
ï‚·
Once we figure out the keys for the first and second locks,
there are only 3
keys left. In the worst case scenario, we will ha
ve to try all 3 keys to open
the third lock.
ï‚·
Once we figure out the keys for the first, second and third locks,
there are
only 2 keys left. In the worst case scenario, we will have to try all
2
keys to
open
the third lock.
ï‚·
The last key is for the last loc
k. It will only take 1 trial to open the last lock.
Altogether, it takes
at least 5 + 4 + 3 + 2 + 1 = 15
trials to
guarantee
us to
open all locks.
Rewards for Problems of the week:
5 stars for the correct answer at your level; 10 stars for the next level; 20 stars for 2+ levels up.
Lower Elementary:
Question: Ethan is making a friendship bracelet with colored beads. The beads follow the pattern red, orange, yellow, green, blue, purple, red, orange, yellow, green, blue, purple, and so on. What color is the 26th bead on the bracelet?
Upper Elementary:
Question: A small bowl can hold 12 apples. A large bowl can hold 20 apples. If Benjamin has 132 apples and already has 6 small bowls, how many large bowls does he need for the rest of the apples?
Middle School:
Question: Laura K has 6 less than 3 times the number of marbles that Laura P has. Laura P has 2 more than half as many marbles as Laura W. If Laura W has 12 marbles, then how many marbles does Laura K have?
Algebra and Up:
Question: Bryan has two snow globes. The glass sphere of the larger snow globe has a radius 3 times that of the smaller snow globe. If the larger snow globe’s glass sphere has a volume of 972π cubic centimeters, then what is the volume of the smaller snow globe’s glass sphere?
Challenge problem to take home. 5 stars for the correct answer.
The following 5 keys are for the following 5 locked padlocks.
Each key opens one and only one padlock. Different keys open different padlocks. What is the least number of trials needed to guarantee that you will open all 5 padlocks?
ï‚·
There are 5 keys. One of them opens the first lock. If we are extremely
unlucky (the worst case scenario), we will have to try all 5 keys
to open the
first lock.
ï‚·
Once we figure out
the key
for the first lock,
there are 4 keys left.
In the
worst case scenario, we will have to try all 4 keys to open the second lock.
ï‚·
Once we figure out the keys for the first and second locks,
there are only 3
keys left. In the worst case scenario, we will ha
ve to try all 3 keys to open
the third lock.
ï‚·
Once we figure out the keys for the first, second and third locks,
there are
only 2 keys left. In the worst case scenario, we will have to try all
2
keys to
open
the third lock.
ï‚·
The last key is for the last loc
k. It will only take 1 trial to open the last lock.
Altogether, it takes
at least 5 + 4 + 3 + 2 + 1 = 15
trials to
guarantee
us to
open all locks.
ï‚·
There are 5 keys. One of them opens the first lock. If we are extremely
unlucky (the worst case scenario), we will have to try all 5 keys
to open the
first lock.
ï‚·
Once we figure out
the key
for the first lock,
there are 4 keys left.
In the
worst case scenario, we will have to try all 4 keys to open the second lock.
ï‚·
Once we figure out the keys for the first and second locks,
there are only 3
keys left. In the worst case scenario, we will ha
ve to try all 3 keys to open
the third lock.
ï‚·
Once we figure out the keys for the first, second and third locks,
there are
only 2 keys left. In the worst case scenario, we will have to try all
2
keys to
open
the third lock.
ï‚·
The last key is for the last loc
k. It will only take 1 trial to open the last lock.
Altogether, it takes
at least 5 + 4 + 3 + 2 + 1 = 15
trials to
guarantee
us to
open all locks.
(919) 510-5553
(919) 510-5553
