Algebra and Up:
Question: It's 9:31 AM and Alfred is running late for his wedding. He runs 500 yards to catch a taxi, which takes him 12 miles to the church at an average rate of 30 miles per hour. If Alfred makes it to the church exactly on time at 10:00 AM, then what is his average running speed per second or 5 feet per second.
Answer: 12/3 yards per second or 5 feet per second.
Solution: The taxi travels 12 miles in 24 minutes, and 24 minutes before 10:00 am is 9:36 am, 5 minutes after he starts running. He runs 500 yards in 5 minutes, and since 5 minutes is 300 seconds, that means he runs 500 ÷ 300 = 12/3 yards per second, which is equal to 5 feet per second.
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